Function unref

unref<T>(ref): T
Returns the inner value if the argument is a ref, otherwise return the argument itself. This is a sugar function for val = isRef(val) ? val.value : val.
Type Parameters
- T
Parameters
- ref: MaybeRef<T>
  Ref or plain value to be converted into the plain value.
Returns T
Example
```
function useFoo(x: number | Ref<number>) {
  const unwrapped = unref(x)
  // unwrapped is guaranteed to be number now
}
```